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legolas007
CodingInterview
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Solution37.java
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37 lines (36 loc) · 1.38 KB
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Solution37.java
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package com.usher.algorithm.offer;
/**
* @Author: Usher
* @Description:
* 序列化二叉树
序列化:使用前序遍历,递归的将二叉树的值转化为字符,并且在每次二叉树的结点
不为空时,在转化val所得的字符之后添加一个' , '作为分割。对于空节点则以 '#' 代替。
反序列化:按照前序顺序,递归的使用字符串中的字符创建一个二叉树(特别注意:
在递归时,递归函数的参数一定要是char ** ,这样才能保证每次递归后指向字符串的指针会
随着递归的进行而移动
*/
public class Solution37 {
int index = -1;
String Serialize(TreeNode root) {
StringBuffer stringBuffer = new StringBuffer();
if (root == null) {
stringBuffer.append("#,");
return stringBuffer.toString();
}
stringBuffer.append(root.val + ",");
stringBuffer.append(Serialize(root.left));
stringBuffer.append(Serialize(root.right));
return stringBuffer.toString();
}
TreeNode Deserialize(String str) {
index++;
String[] strings = str.split(",");
TreeNode node = null;
if (!strings[index].equals("#")){
node = new TreeNode((Integer.valueOf(strings[index])));
node.left = Deserialize(str);
node.right = Deserialize(str);
}
return node;
}
}
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